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A building has 3 identical rectangular parking lots.The sum of the perimeters of the 3 parking lots is 540 feet.If the width of each parking lot is 40 feet,how many feet long is…

A building has 3 identical rectangular parking lots.The sum of the perimeters of the 3 parking lots is 540 feet.If the width of each parking lot is 40 feet,how many feet long is…
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A building has 3 identical rectangular parking lots.The sum of the perimeters of the 3 parking lots is 540 feet.If the width of each parking lot is 40 feet,how many feet long is each parking lot?

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User Abhishek Honrao
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1 Answer

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Each parking lot would be 50 feet long because 540/3=180. 180-(40*2)= 100 and 100/2= 50
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User Walker Boh
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