asked 186k views
2 votes
Triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3). The image of triangle RST after a rotation has vertices

R'(0, –2), S'(0, –4), and T'(–3, –1). Which rule describes the transformation?


R0, 90°

R0, 180°

R0, 270°

R0, 360°

asked
User Gurinder
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8.6k points

2 Answers

3 votes

Answer:

It is C 270

Explanation:

just took the test

answered
User Alan Kazbekov
by
8.8k points
4 votes

Answer:

The correct option is C.

Explanation:

It is given that the triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3) and the image has vertices R'(0, –2), S'(0, –4), and T'(–3, –1). .

From the given vertices it is clear that the relation between preimage and image is defined as


(x,y)\rightarrow (y,-x)

This is the rule of rotation, when the figure rotates 90 degree clockwise adn 270 degree counter clock wise.

R0, 270° represents 270 degree rotation counter clock wise about the origin.

Therefore correct option is C.

Triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3). The image of triangle RST-example-1
answered
User Bless Yahu
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8.0k points