Question

How many liters of chlorine gas, at standard temperature and pressure, will react with 15.5 grams of potassium metal? Show all of the work used to solve this problem. 2K + Cl2 yields 2KCl

Answer 1

2K +Cl₂ --> 2KCl

First calculate how many moles we have of potassium.

15.5 g * (mol/39.0983 g) = 0.396 mol K

2 moles of K reacts with 1 mole of Cl₂, so we know we'll need 0.198 moles of Cl₂.

Standard temperature and pressure is 273.15 degrees K and 1 atm.

Using the gas law PV = nRT, with R = 0.0821 L*atm*K^-1 *mol^-1, you should be able to solve for V, volume, in Liters.