Question

A car is traveling at a velocity of 20 m/s. the driver applies the brakes, and the car slows with an acceleration of a = -4.0 meters per second squared. what is the stopping difference of the car?

Answer 1

`\displaystyle\\ V = a* t\\\\ t= (V)/(a) = (20)/(4) = 5~s\\\\ D = (a* t^2)/(2) = (4* 5^2)/(2) = 2 * 25 = 50~m`