Question

What are the zeros of the function?

g(x)=x3−x2−12x

Select each correct answer.

​ x=−4 ​

x=−3

x = 0

x = 3

x = 4

Answer 1

-3,0,4

Explanation:

This is what i got

Answer 2

x^3−x^2−12x=0

x(x^2-x-12)=0

x(x^2-4x+3x-12)=0

x(x(x-4)+3(x-4))=0

x(x+3)(x-4)=0

So the "zeros" are:

x=(-3,0,4)