Question

Use substitution to solve.

2x² = 5 + y
4y = -20 + 8x²
Solve the first equation for y and substitute it into the second equation. The resulting equation is

Answer 1

Solve the first equation for y and substitute it into the second equation. The resulting equation is

✔ 8x² - 20 = -20 + 8x²

.

The system has

✔ infinitely many solutions

.

Explanation:

Answer 2

`2x^2= 5 + y\\ 4y = -20 + 8x^2 \\\\ y=2x^2-5\\ 4y = -20 + 8x^2 \\\\ 4(2x^2-5)=-20+8x^2\\ 8x^2-20=8x^2-20\\ 0=0`

The equations are identical. They're satisfied by any pair
`(x,2x^2-5)` where
`x\in\mathbb{R}`.