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4 votes
The shorter leg of a right triangle is 6m shorter than the longer leg. the hypotenuse is 6m longer than the longer leg. find the side lengths of the triangle.

asked
User Cacert
by
8.1k points

1 Answer

3 votes
Short leg = x-6m
Longer leg =x
Hypotenuse = x+6m

x² + (x-6)² =(x+6)²
x² + x²-12x+36 = x²+12x+36
2x²-12x+36= x² +12x+36
2x²-12x+36-36= x² +12x+36-36
2x² - 12x-12x = x²+12x-12x
2x² -24x-x² = x²-x²
x² -24x = 0
x(x-24)=0
x = 24

Short leg = 24-6m = 18
Longer leg =24
Hypotenuse = 24+6m=30

Check
a² + b² = c²
18² +24² =30²
324 +576 = 900
900=900
answered
User Austin
by
7.7k points

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