Question

There are three consecutive numbers. the sum of the first two numbers is 47 more than the third number. what are the three numbers?

Answer 1

x + x + 1 = 47 + x+ 2
2x + 1 = 49 +x
2x +1 -1 = 49-1 +x
2x-x =48 +x-x
x = 48
x+1= 49
x+2=50

48 + (48+ 1) = 47 + (48+ 2)
48 + 49 = 47 + 50
97=97