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4 votes
A parabola, (y - 4)2 = -4(x + 3), is changed to (y - 4)2 = -4(x + 10). How will this affect the graph of the parabola?

asked
User Techarch
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1 Answer

4 votes

\bf \begin{array}{llll} (y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\ \end{array} \qquad \begin{array}{llll} vertex\ ({{ h}},{{ k}})\\ {{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\\\\ -----------------------------\\\\ so\quad \begin{cases} \textit{the equation went from}\\\\ (y-4)^2=-4(x+3)\\\\ to\\\\ (y-4)^2=-4(x+10) \end{cases}

notice the h,k vertex of the first one
notice the second one, notice how "h" changed
answered
User MarkWanka
by
8.3k points

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