Question

Find the vertex form of the following equation by completing the square.
y = 3x^2+6x+8

Answer 1

y = 3x^2 + 6x + 8
y = 3(x^2 + 2x + 1) + 5
y = 3(x+1)^2 + 5
y - 5 = 3(x+)^2