Question

Simplify the following expression

(2x3-x to the second power)(3x to the third power - 2x to the second power)

Answer 1

remember

`(x^m)(x^n)=x^(m+n)`
and FOIL, a way to remember to distribute
First
Outer
Inner
Last
that is an order to multiply the terms

so


`(2x^3-x^2)(3x^3-2x^2)`
FOIL
First: 2x³ times 3x³=2 times x³ times 3 times x³=6x⁶
Outer: 2x³ times -2x²=-4x⁵
Inner: -x² times 3x³=-3x⁵
Last: -x² times -2x²=2x⁴

add them together
6x⁶-4x⁵-3x⁵+2x⁴=
6x⁶-7x⁵+2x⁴

Answer 2

x^4(2x-1)(3x-2)
hope this helps :)