Question

A tank contains a gas mixture of 0.852 atm of He, 685 mmHg of O2, and 455 mmHg of N2. What is the pressure in mmHg of the gas mixture?

Answer 1

P=1787.52mmHg

Step-by-step explanation:

Hello,

By using the Dalton's law of partial pressure, one computes the total pressure including the proper units conversion as shown below:

`P=P_(He)+P_(O_2)+P_(N_2)\\P=0.852atm*(760mmHg)/(1atm) +685mmHg+455mmHg\\P=1787.52mmHg`

Best regards.

Answer 2

the pressure of the gas mixture is just equal to the sum of the partial pressure of each gas present in the tank
total pressure = P_he + P_O2 + P_N2
total pressure = 0.852 mm Hg + 685 mm hg + 455 mm hg
total pressure = 1140.852 mm hg