Question

What is the value of h when the function is converted to vertex form? Note: Vertex form is f(x)=a(x−h^)2+k . f(x)=x^2+10x+35

Answer 1

hack: the x value of the vertex (or h) can be found directily from f(x)=ax²+bx+c

so

for f(x)=ax²+bx+c,
`h= (-b)/(2a)`
so
given

f(x)=1x²+10x+35,
`h= (-10)/(2(1))`=-5

h=-5