Question

The width of a rectangle is 7 less than twice the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the rectangle?

Answer 1

I hope this helps you


w = 2l-7


2 (2l-7+l)=43,6


3l-7=21,8


3l=28,8l=9,6


w=2.9,6-7=12,2



Area=9,6.12,2=117,12