Question

Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

6-inch side.

A = sq. in.

Answer 1

A= (1/2) b*h
h=3 sqrt3
A= (1/2)*6*3sqrt3
A= 9sqrt3 square inches

Answer 2

The area of the triangle is 9√3 in²

Explanation:

We know that, the area of an equilateral triangle is,

`A=(√(3))/(4)a^2`

Where, a is the side of the triangle,

Given,

a = 6 inches,

Thus, the area of the given equilateral triangle is,

`A=(√(3))/(4)(6)^2`

`=(36√(3))/(4)`

`=9√(3)\text{ square inches}`