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Identify the translation rule on a coordinate plane that verifies that square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) are congruent.

A)
(x, y) → (x - 1, y - 1)


B)
(x, y) → (x - 1, y + 1)


C)
(x, y) → (x + 1, y + 1)


D)
the squares are not congruent

2 Answers

0 votes
Note that each x value increases by 1 and y values also increases by 1

C is the correct option
answered
User John Bartholomew
by
8.0k points
1 vote

Answer:

The translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

Explanation:

We are given the vertices of a square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) .

We have to find the translation rule on a coordinate plane that verifies that square ABCD is congruent to square A'B'C'D'.

Since, the two squares o be congruent every vertex must be translated by the same rule.

So, the rule is:

(x, y) → (x + 1, y + 1)

since,

A(-4,3) → A'(-4+1,3+1)=A'(-3,4)

B(-4,8) →B'(-4+1,8+1)=(-3,9)

C(-9,3) → C'(-9+1,3+1)=(-8,4)

and D(-9,8) → D'(-9+1,8+1)=(-8,9)

Hence, the translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

answered
User Jakegarbo
by
8.9k points

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