Question

PLEASE HELP LAW OF COSINES

Find the measure of J, the smallest angle in a triangle with sides measuring 11, 13, and 19. Round to the nearest whole degree.

30°
34°
42°
47°

Answer 1

34 degrees

Explanation:

edg quiz

Answer 2

The Law of Cosine states
cos
`C=(a^2+b^2-c^2)/2ab`

so plugging in the numbers gives us

cos
`J=(13^2+19^2-11^2)/2(13*19) = 409/494`

We now have cosJ so plug that into your calculator and find arccos (arccos(cos(J)) = J)
arccos
`(409/494)=34.11`
rounding your answer will give you 34°