Question

Evaluate 3+√x+19-√2x when x=6. Write the answer as a decimal. Round to the nearest hundredth if necessary.

A.


4.54


B.


11.46


C.


7


D.


–4

Answer 1

3+√x+19-√2x replace x by 6===> 3+√6+19-√2*6 = 3+√6+19-√12

Note that √12 = √2x6 = √2 x √6 ===>3+√6+19-(√2) x (√6)

=√6(1+√2)+22