A photon has a wavelength of 624 nm. calculate the energy of the photon in joules

Question

asked Dec 23, 2018 86.8k views

1 Answer

Bain · Answer 1 · 2018-12-28T13:00:44+0000

Answer: The energy of the photon is
3.185* 10^(-19)J

Step-by-step explanation:

To calculate the energy of the photon, we use the equation given by Planck which is:

$\Delta E=(hc)/(\lambda)$

where,

$\lambda$ = Wavelength of the photon =
624nm=6.24* 10^(-7)m (Conversion factor:
1m=10^9nm )

h = Planck's constant =
6.624* 10^(-34)Js

c = speed of light =
3* 10^8m/s

$\Delta E$ = energy of the photon

Putting values in above equation, we get:

$E=(6.624* 10^(-34)* 3* 10^8)/(6.24* 10^(-7))\\\\E=3.185* 10^(-19)J$

Hence, the energy of the complex is
3.185* 10^(-19)J