Question

System of equation by elimination 4x-6y=10 and 3x+6y=4

Answer 1

Solving:


`\left \{ {{4x-6y=10\:(I)} \atop {3x+6y=4\:(II)}} \right.`


`\left \{ {{4x-\diagup\!\!\!\!\!6y=10} \atop {3x+\diagup\!\!\!\!\!6y=4}} \right.`


`\left \{ {{4x=10} \atop {3x=4}} \right.`
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`7x = 14`

`x = (14)/(7)`

`\boxed{\boxed{x = 2}}\end{array}}\qquad\quad\checkmark`

Now replace the found value of "x" in equation (II) to find the value of "y"


`3x+6y=4\:(II)`

`3*(2) + 6y = 4`

`6 + 6y = 4`

`6y = 4 - 6`

`6y = - 2`

`y = (-2)/(6) (/2)/(/2) \to \boxed{\boxed{y = (-1)/(3)}} \end{array}}\qquad\quad\checkmark`

Answer:
x = 2
y = - 1/3