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​ f(x)=x^2−8x+19 ​ . What is the minimum value of the function?​

​ f(x)=x^2−8x+19 ​ . What is the minimum value of the function?​
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​ f(x)=x^2−8x+19 ​ . What is the minimum value of the function?​

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User Alex Kellner
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2 Answers

4 votes
The minimum value for the function is 19 because if the x is 0 then the f(x) is 19. Therefore 19 is the lowest.
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User Dweeberly
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Answer:

Explanation

I took the test its ANS: 3

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User Bryan Menard
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