Question

The ages of 10 friends are consecutive integers. The sum of their ages is 710. they get together every Tuesday to play cards and enjoy each other's company calculate their ages

Answer 1

x = 66.5

x + 1 = 67.5

x + 2 = 68.5

x + 3 = 69.5

x + 4 = 70.5

x + 5 = 71.5

x + 6 = 72. 5

x + 7 = 73.5

x + 8 = 74.5

x + 9 = 84.5

Explanation:

Given that :

Age of 10 friends are consecutive integers :

Let the ages be :

x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9

The sum of their ages = 710

Hence,

x + x+1 + x+2 + x+3 + x+4 + x+5 + x+6 + x+7 + x+8 + x+9 = 710

10x + 45 = 710

10x = 710 - 45

10x = 665

x = 665 / 10

x = 66.5

x + 1 = 67.5

x + 2 = 68.5

x + 3 = 69.5

x + 4 = 70.5

x + 5 = 71.5

x + 6 = 72. 5

x + 7 = 73.5

x + 8 = 74.5

x + 9 = 84.5