asked 46.0k views
1 vote
Find Derivative
(root3(6x^2))

asked
User Eliavs
by
8.4k points

2 Answers

5 votes

\bf \sqrt[3]{6x^2}\implies (6x^2)^{(1)/(3)}\implies 6^{(1)/(3)}x^{(2)/(3)}\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=6^{(1)/(3)}\cdot \cfrac{2}{3}x^{(2)/(3)-1}\implies 6^{(1)/(3)}\cdot \cfrac{2}{3}x^{-(1)/(3)}\implies 6^{(1)/(3)}\cdot \cfrac{2}{3}\cdot \cfrac{1}{x^{(1)/(3)}} \\\\\\


\bf \cfrac{dy}{dx}=6^{(1)/(3)}\cdot \cfrac{2}{3x^{(1)/(3)}}\implies \cfrac{2\cdot 6^{(1)/(3)}}{3x^{(1)/(3)}}\implies \cfrac{2\sqrt[3]{6}}{3\sqrt[3]{x}}\implies \cfrac{2}{3}\sqrt[3]{\cfrac{6}{x}}
answered
User AlphaModder
by
8.2k points
3 votes
This is the same as saying (6x^2)^3. We can take the derivative using the chain rule. With the chain rule, you multiply by the power, decrease the power by 1, and multiply by the derivative of the inside.

3(6x^2)^2*12x
or
36x*(6x^2)^2

Hope this helps
answered
User Ed Manet
by
8.2k points

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