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Fit a quadratic function to these three points: (−1, −11), (0, −3), and (3, −27) y = −4x2 − 4x − 3 y = −4x2 + 4x − 3 y = −4x2 − 4x + 3 y = 4x2 − 4x − 3
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Fit a quadratic function to these three points: (−1, −11), (0, −3), and (3, −27) y = −4x2 − 4x − 3 y = −4x2 + 4x − 3 y = −4x2 − 4x + 3 y = 4x2 − 4x − 3
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Aug 11, 2018
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Fit a quadratic function to these three points:
(−1, −11), (0, −3), and (3, −27)
y = −4x2 − 4x − 3
y = −4x2 + 4x − 3
y = −4x2 − 4x + 3
y = 4x2 − 4x − 3
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Creighton
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You cant so if your teacher assigned this to you she mistakened.
Guto Araujo
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Aug 15, 2018
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Guto Araujo
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