Question

a town has a population of 18000 and grows at 2% every year, What will be the population after 11 years, to the nearest whole number

Answer 1

Explanation:

we have 18,000 people

growth 2% per year

time=11 years

18,000*2/100=360 growth per year

360*11=3,960.00

18,000+3,960=14,960

Answer 2

The population after 11 years is approximately 22,381

How to determine the population growth.

the population after 11 years with a 2% annual growth rate is determined using the formula for exponential growth:

`p = p {(1 + r)}^(t)`

where:

P is the future population,

P_0 is the initial population (18000),

r is the growth rate (2% or 0.02), and

t is the time in years (11).

Substitute in the values and calculate:

P = 18000 * (1 + 0.02)¹¹

P = 18000 * (1.02)¹¹

P = 18000 * 1.243396

P approx 22381.128

Rounding to the nearest whole number, the population after 11 years is approximately 22,381.