2n^2+3n-9 factored completely

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asked Jan 27, 2018 201k views

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Prashant Vhasure · Answer 1 · 2018-02-03T00:27:11+0000

we take the factors of 2....2 and 1
factors of -9...-3 and 3

multiply the first numbers we get -6 and second numbers are 3. when we subtract them, we get our middle term of -3.

(2n - 3) (n + 3)

2n^2+3n-9 factored completely

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