Question

Find the 3rd term in geometric sequence whose first term is -8 and whose common ratio is 6

Answer 1

-288

Explanation:

Geometric Sequence is the sequence in which every digit is the same multiplier of its previous digit.

The formula of Geometric Sequence is:
`a_(n) = a_(1)(r)^(n-1)`

Here we have given that, a₁ = -8, r = 6

So, for finding the 3rd term, n = 3

∵
`a_(n) = a_(1)(r)^(n-1)`

∴
`a_(3) = -8(6)^(3-1)`

⇒ a₃ = -8 × 36 = -288

Thus, third term is -288.