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PLZ HELP!!!!!!!!!!!! A rectangle has a perimeter of 48 feet and a length of 14 feet. Which equation can you solve to find the width? A)2n+28=48 B) 48−n=28 C) 14+n=48 D2n+14=48

PLZ HELP!!!!!!!!!!!! A rectangle has a perimeter of 48 feet and a length of 14 feet. Which equation can you solve to find the width? A)2n+28=48 B) 48−n=28 C) 14+n=48 D2n+14=48
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PLZ HELP!!!!!!!!!!!!

A rectangle has a perimeter of 48 feet and a length of 14 feet. Which equation can you solve to find the width?
A)2n+28=48
B) 48−n=28
C) 14+n=48
D2n+14=48

asked
User Nisus
by
7.5k points

1 Answer

4 votes
P = 2l + 2w
48 = 2(14) + 2w
48 = 28 + 2w

Therefore you could use the equation A.) 2n + 28 = 48, to find the value of N.
answered
User He Shiming
by
8.8k points
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