Question

The coordinates of the vertices of △JKL△JKL are J(1,4)J(1,4), K(6,4)K(6,4), and L(1,1)L(1,1). The coordinates of the vertices of △J′K′L′△J′K′L′ are J′(0,−4)J′(0,−4), K′(−5,−4)K′(−5,−4), and L′(0,−1)L′(0,−1). What is the sequence of transformations that maps △JKL△JKL to △J′K′L′△J′K′L′ ?

Answer 1

how about try it is rotate 90* counterclockwise about the origin and translated 1 unit left that's how you get the right answer

took the test too so

Answer 2

Solution: The ΔJKL reflect along the x-axis, then reflects along the y-axis after that translate 1 unit right to transform ΔJ'K'L'.

Step-by-step explanation:

The vertices of ΔJKL lies in first quadrant because the coordinated of the vertices are positive. It means the vertices are in the form of (x,y).

If the ΔJKL reflects along the x-axis then the vertices are in the form of (x,-y). Now the ΔJKL reflects along the y-axis then the vertices are in the form of (-x,-y).

The given coordinates of the the vertices after transformation is J'(0,-4), K'(-5,-4), L'(0,-1). But after reflection along x and y axis the vertices of ΔJKL are J'(-1,-4), K'(-6,-4), L'(-1,-1). Since the y coordinates are same so we have to tralanate horizontally. Since the difference between x coordinates is positive 1, so we have translate the triangle 1 unit right.

Therefore, the ΔJKL reflect along the x-axis, then reflects along the y-axis after that translate 1 unit right to transform ΔJ'K'L'.