Question

Solve for X. Use the completing the squares method. Round decimals to the nearest tenth: 2x^2+6x=5

Answer 1

Simple...

you have:
`2 x^(2) +6x=5`

Remember, you must first move all terms to the left to reduce.

--->>


`2x^(2) +6-5=0`

Using
`((b)/(2) ) ^(2)` in order to create a new term, and then solve for x by completing the square with this term-->>

x=
`- (3)/(2), (+/-) ( √(19) )/(2)`

Thus, your answer.