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The vertex of f(x)=x^2+4x+12

The vertex of f(x)=x^2+4x+12
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The vertex of f(x)=x^2+4x+12

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User Charnetta
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Answer: y=(x+2)^2-16

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User Nicholas Betts
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Download mathpapa it helps alot on math problems!
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User Mark Murphy
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