Question

against at -20 degree centigrade occupied the volume of one 40 ml calculate the temperature at which the volume of cash pickup 65ml pressure remain constant​

Answer 1

The final temperature :T₂=411.125 K = 138.125 °C

Further explanation

Given

T₁=-20 °C+273 = 253 K

V₁=40 ml

V₂=65 ml

Required

Final temperature

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

`\tt (V_1)/(T_1)=(V_2)/(T_2)`

Input the value :

T₂=(V₂.T₁)/V₁

T₂=(65.253)/40

T₂=411.125 K = 138.125 °C