Question

a calf weighs wo pounds at birth gains wight at the rat dw/dt= 1200-w where w is wight in pounds and t is time in years

Answer 1

`(\mathrm dw)/(\mathrm dt)=1200-w`

`(\mathrm dw)/(w-1200)=-\mathrm dt`

`\displaystyle\int(\mathrm dw)/(w-1200)=-\int\mathrm dt`

`\ln|w-1200|=-t+C`

`e^(\ln|w-1200|)=e^(-t+C)`

`w-1200=Ce^(-t)`

`w=1200+Ce^(-t)`