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24 votes
Determine the number and types of solutions for

6m^2-3m-4=0

asked
User Alborozd
by
8.6k points

1 Answer

5 votes

Given:

The equation is


6m^2-3m-4=0

To find:

The number and types of solutions for the given equation.

Solution:

We have,


6m^2-3m-4=0

It is a 2nd degree polynomial because the highest degree of the variable x is 2.

Number of solutions = Degree of the polynomial

Number of solutions = 2

Therefore, the given equation has 2 solutions.

In a quadratic equation
ax^2+bx+c=0, if
b^2-4ac>0, then the equation has two distinct real solutions.

For the given equation, a=6, b=-3 and c=-4.


D=b^2-4ac


D=(-3)^2-4(6)(-4)


D=9+96


D=105>0

Therefore, the given equation has two distinct real solutions.

answered
User Elprl
by
8.0k points

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