Question

How do I do this???

Consider the chemical reaction 2NH3(g) N2(g) + 3H2(g). The equilibrium is to be established in a 1.0-L container at 1000 K, where Kc = 4.0 × 10–2. Initially, 1.22 moles of NH3(g) are present. What is the equilibrium concentration of H2(g)?

Answer 1

The chemical reaction is as follows:

2NH3(g) = N2(g) + 3H2(g)

We do the ice method to answer this.

NH3 N2 H2
I 1.22 0 0
C -2x x 3x
E 1.22 - 2x x 3x

Kc = [h2]^3 [n2] / [nh3]^2
4.0 × 10^–2 = 27x^3(x) / (1.22 - 2x )^2
x = 0.259 mol

H2 = 0.259/1 = 0.259 mol/L