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If s²=19, what is the value of (s+1)(s-1)

If s²=19, what is the value of (s+1)(s-1)
asked 66.7k views
4 votes
If s²=19, what is the value of (s+1)(s-1)

asked
User Zhilong Jia
by
7.6k points

2 Answers

3 votes

Answer:

(s + 1)(s - 1) = s^2 - 1

= 19-1 = 18

Explanation:

(s + 1)(s - 1) = s^2 - 1

= 19-1 = 18

answered
User Bartosz Czerwonka
by
7.7k points
2 votes
(s + 1)(s - 1) = s^2 - 1
= 19-1 = 18
answered
User Ihough
by
7.7k points
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