Question

Three resistors of 10.0 W, 20.0 W, and 25.0 W are connected in parallel across a 100-V battery. What is the equivalent resistance of the circuit and the current flowing through the 10.0-W resistor?

Answer 1

The equivalent resistance of the circuit is approximately 4.76 Ω. The current flowing through the 10.0 Ω resistor is 10 A.

Step-by-step explanation:

To find the equivalent resistance of the circuit, we need to use the formula:

1/Req = 1/R1 + 1/R2 + 1/R3

Plugging in the values, we get:

1/Req = 1/10 + 1/20 + 1/25

Calculating this, we find the equivalent resistance (Req) to be approximately 4.76 Ω.

To find the current flowing through the 10.0 Ω resistor, we can use Ohm's Law:

I = V/R

Plugging in the values, we get:

I = 100/10

Calculating this, we find the current to be 10 A.

Answer 2

In a parallel connection, the equivalent resistance is the summation of the inverse of each individual resistances. It is mathematically expressed as 1/ Req = 1/10 +1/20 + 1/25 = 5.263 ohms. Also, the voltage across each resistor is equal to the input voltage, therefore I = 100 / 10 = 10 Amps. I hope this helped you.