Question

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g sucrose in 1.75 L solution?

Answer 1

0.5/1.75 = 0.285 M Hope this helps

Answer 2

Answer: The molarity of sucrose solution is 0.286 M

Step-by-step explanation:

To calculate the molarity of solution, we use the equation:

`\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}* \text{Volume of solution (in L)}}`

We are given:

Mass of solute (sucrose) = 171 g

Molar mass of sucrose = 342 g/mol

Volume of solution = 1.75 L

Putting values in above equation, we get:

`\text{Molarity of solution}=(171g)/(342g/mol* 1.75L)\\\\\text{Molarity of solution}=0.286M`

Hence, the molarity of sucrose solution is 0.286 M