Question

Jason has two bags with 6 tiles each. The tiles in each bag are shown below: Make 6 squares. The squares are numbered sequentially from 1 to 6. Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing an even tile from the first bag and an even tile from the second bag? 6 over 12 9 over 12 6 over 36 9 over 36

Answer 1

the answer is 9/36

Explanation:

i took the test on flvs and got it right

Answer 2

From either bag, you have
`\frac36` chance of drawing an even-numbered tile. Whatever you draw from the first bag is independent of what you draw from the second, which means


`\mathbb P((\text{even from bag 1})\cap(\text{even from bag 2}))=\mathbb P(\text{even from bag 1})*\mathbb P(\text{even from bag 2})=\frac36*\frac36=\frac9{36}`