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What are the zeros of (x)= (3x - 1)(2x + 5) (7x-14) ^2

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User Phyllis
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1 Answer

5 votes
I use my calculator ( TI-84 Plus CE-T)
Y1 (the blue one) = (3x-1)(2x+5)(7x-14)^2
Graph
You have 2 zeros
2nd trace zero
The first one gives x= 1/3 and y = 0
(1/3,0)
The second one gives x= 2 and y= 0
(2,0)
answered
User Erickreutz
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8.0k points

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