How many pounds of nails costing $7 per pound must be mixed with 6 pounds of nails costing $3 per pound to yield a mixture costing $4 per pound?

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asked Sep 14, 2018 70.0k views

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Vitor Tyburski · Answer 1 · 2018-09-21T01:57:19+0000

let nails 7/pound=N1
nails 3/pound=N2

let N1=x
N2=6
then total=x+6
7x+6*3=(x+6)*4
7x+18=4x+24
3x=6
x=2
so 2 pounds on Nails costing 7/pound must be added

How many pounds of nails costing $7 per pound must be mixed with 6 pounds of nails costing $3 per pound to yield a mixture costing $4 per pound?

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