asked 40.7k views
1 vote
Integral of e^(-xdx? can anyone explain how to evaluate the indefinite integral of e^(-xdx using the substitution rule to do u substitution?

1 Answer

4 votes

\displaystyle\int e^(-x)\,\mathrm dx

You probably know that the antiderivative of
e^x is simply
e^x. So to get something that resembles this form, let
u=-x. Then
\mathrm du=-\mathrm dx, or
-\mathrm du=\mathrm dx.

Now the integral is


\displaystyle\int e^(-x)\,\mathrm dx=\int e^u(-\mathrm du)=-\int e^u\,\mathrm du=-e^u+C=-e^(-x)+C
answered
User Guillem Gelabert
by
8.6k points
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