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Find the 11th term of the sequence 11, 19, 27, 35

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User Ivo Leko
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7.8k points

1 Answer

4 votes

Answer:

91

Explanation:

Each term is 8 more than the last, so you can write the terms of the sequence until you get there:

11, 19, 27, 35, 43, 51, 59, 67, 75, 83, 91

__

Or, you can use the formula for the general term of an arithmetic sequence. You have first term a1=11 and common difference d=8.

an = a1 +d(n -1)

a11 = 11 + 8(11 -1) = 11 + 80

a11 = 91

answered
User Gtomika
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