Question

Find the equation of the line that has a slope of 7 and passes through the point (-6,8).

Answer 1

y-y1=m(x-x1)
y-8=7(x-(-6))
y-8=7(x+6)
y-8=7x+42
+8 +8
y=7x+50

Answer 2

y = 7x + 50. Use slope-intercept form (y = mx + b), where m is slope, and b is the y-intercept. Insert the values we already know into the equation. y = 7x + b. Now, insert the x and y-values of your order pair into the equation and solve for b. 8 = 7(-6) + b ---> 8 = -42 + b --> 8 + 42 = -42 + b + 42 --> 50 = b or b = 50. Now that we have the value of b, insert it into the equation as well, and then you have your answer. Answer: y = 7x + 50