Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0 o,one 25,two 30,one which of the 3 is the answer

Question

asked Sep 25, 2018 29.6k views

1 Answer

Canor · Answer 1 · 2018-09-29T03:23:23+0000

I hope this helps you

1.y^2+3y-4 =0

a=1

b=3

c= -4

disctirminant=b^2-4ac

disctirminant=3^2-4.1.(-4)

disctirminant=9+16

disctirminant=25