Question

How many moles of MgS2O3 are in 223 g of the compound

Answer 1

Moles of MgS2O3 = 223/molar mass of MgS2O3

= 223/136.42
= 1.634 moles.

Hope this helps!

Answer 2

Answer: 1.63 moles

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=`

Given mass = 223 g

Molar mass = 136.4

`\text{Number of moles}=(223g)/(136.4g/mol)=1.63moles`

Thus there are 1.63 moles in 223 g of the compound.