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How many moles of MgS2O3 are in 181 g of the compound

How many moles of MgS2O3 are in 181 g of the compound
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How many moles of MgS2O3 are in 181 g of the compound

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User TTeeple
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Moles of MgS2O3 = 181/molar mass of MgS2O3
= 181/136.42
= 1.326 moles.

Hope this helps!
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User Nattgew
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