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Solve the system of equations by elimination. 2x−y+3z=−12x−y+3z=−1 x+2y−4z=−1x+2y−4z=−1 y−2z=0y−2z=0

Solve the system of equations by elimination. 2x−y+3z=−12x−y+3z=−1 x+2y−4z=−1x+2y−4z=−1 y−2z=0y−2z=0
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Solve the system of equations by elimination. 2x−y+3z=−12x−y+3z=−1 x+2y−4z=−1x+2y−4z=−1 y−2z=0y−2z=0

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User SignalRichard
by
8.0k points

1 Answer

5 votes
the solution is
x=0 , y=0 , z=0

answered
User Jck
by
8.1k points
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