Question

EC = 10cm, AE = 4cm, and m∠EAB = 45°. Find the area of the kite. 56cm2 80cm2 112cm2 160cm2

Answer 1

Did the math the comment bro is right it’s 56

Answer 2

Option A is correct i.e Area is 56 square centimeter.

Explanation:

Given EC = 10cm, AE = 4cm, and m∠EAB = 45°. we have to find the area of kite.

In ΔABE, ∠EAB = 45°

`tan\angle EAB=(BE)/(AE)`

⇒
`tan 45^(\circ)=(BE)/(4)`

⇒ BE=4 cm

BE=ED=4 cm (one diagonal of kite bisect other)

BD=BE+ED=4+4=8 cm

AC=AE+EC=4+10=14 cm

`\text{Area of kite=}(pq)/(2)`, where p and q are the diagonals

⇒
`\text{Area of kite ABCD=}(8* 14)/(2)=56cm^2`

Option A is correct.