Question

Find the remainder when the function is
​

Answer 1

according to the question

3x-1=0

3x=1

x=⅓

so

f(x)=18x³+x-1

f(⅓)=18.(⅓)³+⅓-1

f(⅓)=18.⅓.⅓.⅓+⅓-1

f(⅓)=6.⅑+⅓-1

f(⅓)=⅔+½-1

f(⅓)=0

therefore

the remainder is 0